Base | Representation |
---|---|
bin | 1011111100111010111010… |
… | …0111011110110110011011 |
3 | 1201112021211020012202001112 |
4 | 2333032232213132312123 |
5 | 3210301222020402102 |
6 | 43540555543010535 |
7 | 2524265020411412 |
oct | 277165647366633 |
9 | 51467736182045 |
10 | 13141234544027 |
11 | 4207191344057 |
12 | 1582a38a39a4b |
13 | 7442a0247c25 |
14 | 3360795b6479 |
15 | 17bc78969252 |
hex | bf3ae9ded9b |
13141234544027 has 2 divisors, whose sum is σ = 13141234544028. Its totient is φ = 13141234544026.
The previous prime is 13141234543937. The next prime is 13141234544063. The reversal of 13141234544027 is 72044543214131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13141234544027 - 212 = 13141234539931 is a prime.
It is a super-2 number, since 2×131412345440272 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13141234544827) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570617272013 + 6570617272014.
It is an arithmetic number, because the mean of its divisors is an integer number (6570617272014).
Almost surely, 213141234544027 is an apocalyptic number.
13141234544027 is a deficient number, since it is larger than the sum of its proper divisors (1).
13141234544027 is an equidigital number, since it uses as much as digits as its factorization.
13141234544027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 322560, while the sum is 41.
Adding to 13141234544027 its reverse (72044543214131), we get a palindrome (85185777758158).
The spelling of 13141234544027 in words is "thirteen trillion, one hundred forty-one billion, two hundred thirty-four million, five hundred forty-four thousand, twenty-seven".
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