13141300102113 has 4 divisors (see below), whose sum is σ = 17521733469488. Its totient is φ = 8760866734740.

The previous prime is 13141300102111. The next prime is 13141300102141. The reversal of 13141300102113 is 31120100314131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13141300102113 - 2¹ = 13141300102111 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13141300102113.

It is not an unprimeable number, because it can be changed into a prime (13141300102111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2190216683683 + ... + 2190216683688.

It is an arithmetic number, because the mean of its divisors is an integer number (4380433367372).

Almost surely, 2^{13141300102113} is an apocalyptic number.

It is an amenable number.

13141300102113 is a deficient number, since it is larger than the sum of its proper divisors (4380433367375).

13141300102113 is an equidigital number, since it uses as much as digits as its factorization.

13141300102113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4380433367374.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 13141300102113 its reverse (31120100314131), we get a palindrome (44261400416244).

The spelling of 13141300102113 in words is "thirteen trillion, one hundred forty-one billion, three hundred million, one hundred two thousand, one hundred thirteen".