Base | Representation |
---|---|
bin | 11101111000010011111011… |
… | …001110110001011010001011 |
3 | 122020021222000022102021010002 |
4 | 131320103323032301122023 |
5 | 114211032343242421102 |
6 | 1143254151535513215 |
7 | 36452164332350624 |
oct | 3570237316613213 |
9 | 566258008367102 |
10 | 131413034342027 |
11 | 38965a55a56609 |
12 | 128a488738880b |
13 | 58432716c6179 |
14 | 24645d3912a4b |
15 | 102d54bb90902 |
hex | 7784fb3b168b |
131413034342027 has 2 divisors, whose sum is σ = 131413034342028. Its totient is φ = 131413034342026.
The previous prime is 131413034341997. The next prime is 131413034342059. The reversal of 131413034342027 is 720243430314131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131413034342027 - 210 = 131413034341003 is a prime.
It is a super-3 number, since 3×1314130343420273 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (131413034348027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65706517171013 + 65706517171014.
It is an arithmetic number, because the mean of its divisors is an integer number (65706517171014).
Almost surely, 2131413034342027 is an apocalyptic number.
131413034342027 is a deficient number, since it is larger than the sum of its proper divisors (1).
131413034342027 is an equidigital number, since it uses as much as digits as its factorization.
131413034342027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 145152, while the sum is 38.
Adding to 131413034342027 its reverse (720243430314131), we get a palindrome (851656464656158).
The spelling of 131413034342027 in words is "one hundred thirty-one trillion, four hundred thirteen billion, thirty-four million, three hundred forty-two thousand, twenty-seven".
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