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131413034341997 is a prime number
BaseRepresentation
bin11101111000010011111011…
…001110110001011001101101
3122020021222000022102021001222
4131320103323032301121231
5114211032343242420442
61143254151535513125
736452164332350552
oct3570237316613155
9566258008367058
10131413034341997
1138965a55a56591
12128a48873887a5
1358432716c6155
1424645d3912a29
15102d54bb908d2
hex7784fb3b166d

131413034341997 has 2 divisors, whose sum is σ = 131413034341998. Its totient is φ = 131413034341996.

The previous prime is 131413034341993. The next prime is 131413034342027. The reversal of 131413034341997 is 799143430314131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71464265951716 + 59948768390281 = 8453654^2 + 7742659^2 .

It is a cyclic number.

It is not a de Polignac number, because 131413034341997 - 22 = 131413034341993 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131413034341993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65706517170998 + 65706517170999.

It is an arithmetic number, because the mean of its divisors is an integer number (65706517170999).

Almost surely, 2131413034341997 is an apocalyptic number.

It is an amenable number.

131413034341997 is a deficient number, since it is larger than the sum of its proper divisors (1).

131413034341997 is an equidigital number, since it uses as much as digits as its factorization.

131413034341997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2939328, while the sum is 53.

The spelling of 131413034341997 in words is "one hundred thirty-one trillion, four hundred thirteen billion, thirty-four million, three hundred forty-one thousand, nine hundred ninety-seven".