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13141304044322 = 26570652022161
BaseRepresentation
bin1011111100111011001011…
…0000100110101100100010
31201112022000001222201112112
42333032302300212230202
53210301342313404242
643541010504355322
72524266523224236
oct277166260465442
951468001881475
1013141304044322
1142072175a3713
121582a58175b42
137442b177016c
143360849085c6
1517bc7eae6c82
hexbf3b2c26b22

13141304044322 has 4 divisors (see below), whose sum is σ = 19711956066486. Its totient is φ = 6570652022160.

The previous prime is 13141304044307. The next prime is 13141304044457. The reversal of 13141304044322 is 22344040314131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12787339731721 + 353964312601 = 3575939^2 + 594949^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3285326011079 + ... + 3285326011082.

Almost surely, 213141304044322 is an apocalyptic number.

13141304044322 is a deficient number, since it is larger than the sum of its proper divisors (6570652022164).

13141304044322 is an equidigital number, since it uses as much as digits as its factorization.

13141304044322 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6570652022163.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 13141304044322 its reverse (22344040314131), we get a palindrome (35485344358453).

The spelling of 13141304044322 in words is "thirteen trillion, one hundred forty-one billion, three hundred four million, forty-four thousand, three hundred twenty-two".

Divisors: 1 2 6570652022161 13141304044322