Base | Representation |
---|---|
bin | 1011111100111011001011… |
… | …0000111111010010101111 |
3 | 1201112022000002011211201222 |
4 | 2333032302300333102233 |
5 | 3210301342330120241 |
6 | 43541010510453555 |
7 | 2524266524124044 |
oct | 277166260772257 |
9 | 51468002154658 |
10 | 13141304145071 |
11 | 4207217662383 |
12 | 1582a582042bb |
13 | 7442b17a6c8b |
14 | 3360849331cb |
15 | 17bc7eb16a4b |
hex | bf3b2c3f4af |
13141304145071 has 2 divisors, whose sum is σ = 13141304145072. Its totient is φ = 13141304145070.
The previous prime is 13141304145037. The next prime is 13141304145121. The reversal of 13141304145071 is 17054140314131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13141304145071 - 230 = 13140230403247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13141304145371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570652072535 + 6570652072536.
It is an arithmetic number, because the mean of its divisors is an integer number (6570652072536).
Almost surely, 213141304145071 is an apocalyptic number.
13141304145071 is a deficient number, since it is larger than the sum of its proper divisors (1).
13141304145071 is an equidigital number, since it uses as much as digits as its factorization.
13141304145071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 35.
The spelling of 13141304145071 in words is "thirteen trillion, one hundred forty-one billion, three hundred four million, one hundred forty-five thousand, seventy-one".
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