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13141312102489 is a prime number
BaseRepresentation
bin1011111100111011001100…
…1111010110000001011001
31201112022000122011010021011
42333032303033112001121
53210301401344234424
643541011353213521
72524266651555364
oct277166317260131
951468018133234
1013141312102489
1142072210a795a
121582a5aa012a1
137442b3331bcc
14336085a050db
1517bc80689694
hexbf3b33d6059

13141312102489 has 2 divisors, whose sum is σ = 13141312102490. Its totient is φ = 13141312102488.

The previous prime is 13141312102469. The next prime is 13141312102559. The reversal of 13141312102489 is 98420121314131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12707143125264 + 434168977225 = 3564708^2 + 658915^2 .

It is a cyclic number.

It is not a de Polignac number, because 13141312102489 - 29 = 13141312101977 is a prime.

It is not a weakly prime, because it can be changed into another prime (13141312102459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570656051244 + 6570656051245.

It is an arithmetic number, because the mean of its divisors is an integer number (6570656051245).

Almost surely, 213141312102489 is an apocalyptic number.

It is an amenable number.

13141312102489 is a deficient number, since it is larger than the sum of its proper divisors (1).

13141312102489 is an equidigital number, since it uses as much as digits as its factorization.

13141312102489 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 40.

The spelling of 13141312102489 in words is "thirteen trillion, one hundred forty-one billion, three hundred twelve million, one hundred two thousand, four hundred eighty-nine".