Base | Representation |
---|---|
bin | 11101111000010100001011… |
… | …110101110100011010011111 |
3 | 122020021222201201210020101022 |
4 | 131320110023311310122133 |
5 | 114211033431112412112 |
6 | 1143254235332434355 |
7 | 36452204255125625 |
oct | 3570241365643237 |
9 | 566258651706338 |
10 | 131413313013407 |
11 | 38966089292537 |
12 | 128a49447789bb |
13 | 58432b7366b89 |
14 | 246461c933515 |
15 | 102d566389d72 |
hex | 77850bd7469f |
131413313013407 has 2 divisors, whose sum is σ = 131413313013408. Its totient is φ = 131413313013406.
The previous prime is 131413313013377. The next prime is 131413313013439. The reversal of 131413313013407 is 704310313314131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131413313013407 - 212 = 131413313009311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131413313013007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65706656506703 + 65706656506704.
It is an arithmetic number, because the mean of its divisors is an integer number (65706656506704).
Almost surely, 2131413313013407 is an apocalyptic number.
131413313013407 is a deficient number, since it is larger than the sum of its proper divisors (1).
131413313013407 is an equidigital number, since it uses as much as digits as its factorization.
131413313013407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27216, while the sum is 35.
Adding to 131413313013407 its reverse (704310313314131), we get a palindrome (835723626327538).
The spelling of 131413313013407 in words is "one hundred thirty-one trillion, four hundred thirteen billion, three hundred thirteen million, thirteen thousand, four hundred seven".
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