131413320024041 has 4 divisors (see below), whose sum is σ = 143359985480784. Its totient is φ = 119466654567300.

The previous prime is 131413320024029. The next prime is 131413320024047. The reversal of 131413320024041 is 140420023314131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131413320024041 - 2⁴² = 127015273512937 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131413320023995 and 131413320024013.

It is not an unprimeable number, because it can be changed into a prime (131413320024047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5973332728355 + ... + 5973332728376.

It is an arithmetic number, because the mean of its divisors is an integer number (35839996370196).

Almost surely, 2^{131413320024041} is an apocalyptic number.

131413320024041 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

131413320024041 is a deficient number, since it is larger than the sum of its proper divisors (11946665456743).

131413320024041 is a wasteful number, since it uses less digits than its factorization.

131413320024041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11946665456742.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 131413320024041 its reverse (140420023314131), we get a palindrome (271833343338172).

The spelling of 131413320024041 in words is "one hundred thirty-one trillion, four hundred thirteen billion, three hundred twenty million, twenty-four thousand, forty-one".