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131413340432002 = 265706670216001
BaseRepresentation
bin11101111000010100001101…
…011110011010011010000010
3122020021222210122101020121211
4131320110031132122122002
5114211034010122311002
61143254242152240334
736452205040153336
oct3570241536323202
9566258718336554
10131413340432002
11389660a280a532
12128a49519a00aa
1358432bcc46bb5
14246462242d7c6
15102d5689a3dd7
hex77850d79a682

131413340432002 has 4 divisors (see below), whose sum is σ = 197120010648006. Its totient is φ = 65706670216000.

The previous prime is 131413340431981. The next prime is 131413340432009. The reversal of 131413340432002 is 200234043314131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 123437455078081 + 7975885353921 = 11110241^2 + 2824161^2 .

It is not an unprimeable number, because it can be changed into a prime (131413340432009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32853335107999 + ... + 32853335108002.

Almost surely, 2131413340432002 is an apocalyptic number.

131413340432002 is a deficient number, since it is larger than the sum of its proper divisors (65706670216004).

131413340432002 is an equidigital number, since it uses as much as digits as its factorization.

131413340432002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65706670216003.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 131413340432002 its reverse (200234043314131), we get a palindrome (331647383746133).

The spelling of 131413340432002 in words is "one hundred thirty-one trillion, four hundred thirteen billion, three hundred forty million, four hundred thirty-two thousand, two".

Divisors: 1 2 65706670216001 131413340432002