Base | Representation |
---|---|
bin | 10011000111111000011… |
… | …101001101011101010001 |
3 | 11122122000012220012021222 |
4 | 103013320131031131101 |
5 | 133012321124312040 |
6 | 2443412104054425 |
7 | 163641310604042 |
oct | 23077035153521 |
9 | 4578005805258 |
10 | 1314133432145 |
11 | 467359076a26 |
12 | 192830764415 |
13 | 96bcb254041 |
14 | 478666768c9 |
15 | 242b4b13bb5 |
hex | 131f874d751 |
1314133432145 has 4 divisors (see below), whose sum is σ = 1576960118580. Its totient is φ = 1051306745712.
The previous prime is 1314133432123. The next prime is 1314133432189. The reversal of 1314133432145 is 5412343314131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 164196764944 + 1149936667201 = 405212^2 + 1072351^2 .
It is a cyclic number.
It is not a de Polignac number, because 1314133432145 - 218 = 1314133170001 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131413343210 + ... + 131413343219.
It is an arithmetic number, because the mean of its divisors is an integer number (394240029645).
Almost surely, 21314133432145 is an apocalyptic number.
It is an amenable number.
1314133432145 is a deficient number, since it is larger than the sum of its proper divisors (262826686435).
1314133432145 is an equidigital number, since it uses as much as digits as its factorization.
1314133432145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 262826686434.
The product of its digits is 51840, while the sum is 35.
Adding to 1314133432145 its reverse (5412343314131), we get a palindrome (6726476746276).
The spelling of 1314133432145 in words is "one trillion, three hundred fourteen billion, one hundred thirty-three million, four hundred thirty-two thousand, one hundred forty-five".
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