Base | Representation |
---|---|
bin | 11101111000010100010001… |
… | …010001100001010010110011 |
3 | 122020021222222002022000122121 |
4 | 131320110101101201102303 |
5 | 114211034122431124303 |
6 | 1143254252350215111 |
7 | 36452206442641633 |
oct | 3570242121412263 |
9 | 566258862260577 |
10 | 131413404161203 |
11 | 3896612578819a |
12 | 128a496b1b4497 |
13 | 58433001cb398 |
14 | 246462aa9c6c3 |
15 | 102d56e3919bd |
hex | 7785114614b3 |
131413404161203 has 2 divisors, whose sum is σ = 131413404161204. Its totient is φ = 131413404161202.
The previous prime is 131413404161201. The next prime is 131413404161257. The reversal of 131413404161203 is 302161404314131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131413404161203 - 21 = 131413404161201 is a prime.
Together with 131413404161201, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (131413404161201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65706702080601 + 65706702080602.
It is an arithmetic number, because the mean of its divisors is an integer number (65706702080602).
Almost surely, 2131413404161203 is an apocalyptic number.
131413404161203 is a deficient number, since it is larger than the sum of its proper divisors (1).
131413404161203 is an equidigital number, since it uses as much as digits as its factorization.
131413404161203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 34.
Adding to 131413404161203 its reverse (302161404314131), we get a palindrome (433574808475334).
The spelling of 131413404161203 in words is "one hundred thirty-one trillion, four hundred thirteen billion, four hundred four million, one hundred sixty-one thousand, two hundred three".
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