Base | Representation |
---|---|
bin | 1011111100111011010011… |
… | …1110010110111010110111 |
3 | 1201112022002122220122020111 |
4 | 2333032310332112322313 |
5 | 3210301431322013101 |
6 | 43541014313043451 |
7 | 2524300454123026 |
oct | 277166476267267 |
9 | 51468078818214 |
10 | 13141341204151 |
11 | 4207236574416 |
12 | 1582a686b6587 |
13 | 7442b9381024 |
14 | 33608981c8bd |
15 | 17bc82ed7251 |
hex | bf3b4f96eb7 |
13141341204151 has 2 divisors, whose sum is σ = 13141341204152. Its totient is φ = 13141341204150.
The previous prime is 13141341204139. The next prime is 13141341204157. The reversal of 13141341204151 is 15140214314131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13141341204151 - 217 = 13141341073079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13141341204157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570670602075 + 6570670602076.
It is an arithmetic number, because the mean of its divisors is an integer number (6570670602076).
Almost surely, 213141341204151 is an apocalyptic number.
13141341204151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13141341204151 is an equidigital number, since it uses as much as digits as its factorization.
13141341204151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 31.
Adding to 13141341204151 its reverse (15140214314131), we get a palindrome (28281555518282).
The spelling of 13141341204151 in words is "thirteen trillion, one hundred forty-one billion, three hundred forty-one million, two hundred four thousand, one hundred fifty-one".
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