Base | Representation |
---|---|
bin | 1011111100111011010100… |
… | …0110001000010001010110 |
3 | 1201112022002210202010200112 |
4 | 2333032311012020101112 |
5 | 3210301432332210202 |
6 | 43541014424443022 |
7 | 2524300510336163 |
oct | 277166506102126 |
9 | 51468083663615 |
10 | 13141343241302 |
11 | 4207237735a11 |
12 | 1582a69319472 |
13 | 7442b9915343 |
14 | 336089bcd06a |
15 | 17bc8328ab52 |
hex | bf3b5188456 |
13141343241302 has 4 divisors (see below), whose sum is σ = 19712014861956. Its totient is φ = 6570671620650.
The previous prime is 13141343241251. The next prime is 13141343241371. The reversal of 13141343241302 is 20314234314131.
13141343241302 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3285335810324 + ... + 3285335810327.
It is an arithmetic number, because the mean of its divisors is an integer number (4928003715489).
Almost surely, 213141343241302 is an apocalyptic number.
13141343241302 is a deficient number, since it is larger than the sum of its proper divisors (6570671620654).
13141343241302 is an equidigital number, since it uses as much as digits as its factorization.
13141343241302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6570671620653.
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 13141343241302 its reverse (20314234314131), we get a palindrome (33455577555433).
The spelling of 13141343241302 in words is "thirteen trillion, one hundred forty-one billion, three hundred forty-three million, two hundred forty-one thousand, three hundred two".
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