Base | Representation |
---|---|
bin | 1011111100111011010100… |
… | …0111001100110101111101 |
3 | 1201112022002211021101222011 |
4 | 2333032311013030311331 |
5 | 3210301432420202143 |
6 | 43541014434451221 |
7 | 2524300512616066 |
oct | 277166507146575 |
9 | 51468084241864 |
10 | 13141343522173 |
11 | 4207237907a39 |
12 | 1582a69433b11 |
13 | 7442b99b3139 |
14 | 336089c6356d |
15 | 17bc832e3e9d |
hex | bf3b51ccd7d |
13141343522173 has 2 divisors, whose sum is σ = 13141343522174. Its totient is φ = 13141343522172.
The previous prime is 13141343522147. The next prime is 13141343522191. The reversal of 13141343522173 is 37122534314131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12805826861529 + 335516660644 = 3578523^2 + 579238^2 .
It is a cyclic number.
It is not a de Polignac number, because 13141343522173 - 25 = 13141343522141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13141343522123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570671761086 + 6570671761087.
It is an arithmetic number, because the mean of its divisors is an integer number (6570671761087).
Almost surely, 213141343522173 is an apocalyptic number.
It is an amenable number.
13141343522173 is a deficient number, since it is larger than the sum of its proper divisors (1).
13141343522173 is an equidigital number, since it uses as much as digits as its factorization.
13141343522173 is an evil number, because the sum of its binary digits is even.
The product of its digits is 181440, while the sum is 40.
The spelling of 13141343522173 in words is "thirteen trillion, one hundred forty-one billion, three hundred forty-three million, five hundred twenty-two thousand, one hundred seventy-three".
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