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13141343522173 is a prime number
BaseRepresentation
bin1011111100111011010100…
…0111001100110101111101
31201112022002211021101222011
42333032311013030311331
53210301432420202143
643541014434451221
72524300512616066
oct277166507146575
951468084241864
1013141343522173
114207237907a39
121582a69433b11
137442b99b3139
14336089c6356d
1517bc832e3e9d
hexbf3b51ccd7d

13141343522173 has 2 divisors, whose sum is σ = 13141343522174. Its totient is φ = 13141343522172.

The previous prime is 13141343522147. The next prime is 13141343522191. The reversal of 13141343522173 is 37122534314131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12805826861529 + 335516660644 = 3578523^2 + 579238^2 .

It is a cyclic number.

It is not a de Polignac number, because 13141343522173 - 25 = 13141343522141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13141343522123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570671761086 + 6570671761087.

It is an arithmetic number, because the mean of its divisors is an integer number (6570671761087).

Almost surely, 213141343522173 is an apocalyptic number.

It is an amenable number.

13141343522173 is a deficient number, since it is larger than the sum of its proper divisors (1).

13141343522173 is an equidigital number, since it uses as much as digits as its factorization.

13141343522173 is an evil number, because the sum of its binary digits is even.

The product of its digits is 181440, while the sum is 40.

The spelling of 13141343522173 in words is "thirteen trillion, one hundred forty-one billion, three hundred forty-three million, five hundred twenty-two thousand, one hundred seventy-three".