Base | Representation |
---|---|
bin | 11101111000010100111010… |
… | …111100010000111100101111 |
3 | 122020022001202210201111220211 |
4 | 131320110322330100330233 |
5 | 114211042040411413203 |
6 | 1143254450001523251 |
7 | 36452232661644043 |
oct | 3570247274207457 |
9 | 566261683644824 |
10 | 131414103232303 |
11 | 38966454352701 |
12 | 128a4b25343527 |
13 | 58433b1ca3a18 |
14 | 2464695874023 |
15 | 102d5b092dc6d |
hex | 77853af10f2f |
131414103232303 has 2 divisors, whose sum is σ = 131414103232304. Its totient is φ = 131414103232302.
The previous prime is 131414103232271. The next prime is 131414103232339. The reversal of 131414103232303 is 303232301414131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131414103232303 - 25 = 131414103232271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131414103232403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65707051616151 + 65707051616152.
It is an arithmetic number, because the mean of its divisors is an integer number (65707051616152).
Almost surely, 2131414103232303 is an apocalyptic number.
131414103232303 is a deficient number, since it is larger than the sum of its proper divisors (1).
131414103232303 is an equidigital number, since it uses as much as digits as its factorization.
131414103232303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 131414103232303 its reverse (303232301414131), we get a palindrome (434646404646434).
The spelling of 131414103232303 in words is "one hundred thirty-one trillion, four hundred fourteen billion, one hundred three million, two hundred thirty-two thousand, three hundred three".
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