Base | Representation |
---|---|
bin | 11101111000010101001100… |
… | …101101000100110011101111 |
3 | 122020022002112120110220001011 |
4 | 131320111030231010303233 |
5 | 114211043143204142203 |
6 | 1143254535325130051 |
7 | 36452243240656036 |
oct | 3570251455046357 |
9 | 566262476426034 |
10 | 131414401240303 |
11 | 38966597596505 |
12 | 128a4ba90b9927 |
13 | 584342b954c0c |
14 | 24646c328971d |
15 | 102d5cbb9776d |
hex | 77854cb44cef |
131414401240303 has 2 divisors, whose sum is σ = 131414401240304. Its totient is φ = 131414401240302.
The previous prime is 131414401240159. The next prime is 131414401240361. The reversal of 131414401240303 is 303042104414131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131414401240303 - 225 = 131414367685871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131414401240373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65707200620151 + 65707200620152.
It is an arithmetic number, because the mean of its divisors is an integer number (65707200620152).
Almost surely, 2131414401240303 is an apocalyptic number.
131414401240303 is a deficient number, since it is larger than the sum of its proper divisors (1).
131414401240303 is an equidigital number, since it uses as much as digits as its factorization.
131414401240303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 131414401240303 its reverse (303042104414131), we get a palindrome (434456505654434).
The spelling of 131414401240303 in words is "one hundred thirty-one trillion, four hundred fourteen billion, four hundred one million, two hundred forty thousand, three hundred three".
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