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13141455414419 is a prime number
BaseRepresentation
bin1011111100111011101111…
…0010000010010010010011
31201112022101121211010021102
42333032323302002102103
53210302200041230134
643541033513015015
72524303341651413
oct277167362022223
951468347733242
1013141455414419
114207294a91272
121582a9a9b446b
13744306c2b877
1433609aa6c643
1517bc8d04737e
hexbf3bbc82493

13141455414419 has 2 divisors, whose sum is σ = 13141455414420. Its totient is φ = 13141455414418.

The previous prime is 13141455414331. The next prime is 13141455414427. The reversal of 13141455414419 is 91441455414131.

It is a strong prime.

It is an emirp because it is prime and its reverse (91441455414131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13141455414419 - 212 = 13141455410323 is a prime.

It is a super-2 number, since 2×131414554144192 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13141455414119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570727707209 + 6570727707210.

It is an arithmetic number, because the mean of its divisors is an integer number (6570727707210).

Almost surely, 213141455414419 is an apocalyptic number.

13141455414419 is a deficient number, since it is larger than the sum of its proper divisors (1).

13141455414419 is an equidigital number, since it uses as much as digits as its factorization.

13141455414419 is an evil number, because the sum of its binary digits is even.

The product of its digits is 691200, while the sum is 47.

The spelling of 13141455414419 in words is "thirteen trillion, one hundred forty-one billion, four hundred fifty-five million, four hundred fourteen thousand, four hundred nineteen".