Base | Representation |
---|---|
bin | 1011111100111011101111… |
… | …0010000010010000111011 |
3 | 1201112022101121211010011011 |
4 | 2333032323302002100323 |
5 | 3210302200041224311 |
6 | 43541033513014351 |
7 | 2524303341651226 |
oct | 277167362022073 |
9 | 51468347733134 |
10 | 13141455414331 |
11 | 4207294a911a2 |
12 | 1582a9a9b43b7 |
13 | 744306c2b80a |
14 | 33609aa6c5bd |
15 | 17bc8d047321 |
hex | bf3bbc8243b |
13141455414331 has 2 divisors, whose sum is σ = 13141455414332. Its totient is φ = 13141455414330.
The previous prime is 13141455414319. The next prime is 13141455414419. The reversal of 13141455414331 is 13341455414131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13141455414331 - 29 = 13141455413819 is a prime.
It is a super-2 number, since 2×131414554143312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13141455412331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570727707165 + 6570727707166.
It is an arithmetic number, because the mean of its divisors is an integer number (6570727707166).
Almost surely, 213141455414331 is an apocalyptic number.
13141455414331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13141455414331 is an equidigital number, since it uses as much as digits as its factorization.
13141455414331 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 172800, while the sum is 40.
The spelling of 13141455414331 in words is "thirteen trillion, one hundred forty-one billion, four hundred fifty-five million, four hundred fourteen thousand, three hundred thirty-one".
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