Base | Representation |
---|---|
bin | 11000011110100110… |
… | …10001111000110011 |
3 | 1020220212021011112022 |
4 | 30033103101320303 |
5 | 203403223123011 |
6 | 10012010222055 |
7 | 643442606552 |
oct | 141723217063 |
9 | 36825234468 |
10 | 13141614131 |
11 | 563410a228 |
12 | 266912492b |
13 | 1315825949 |
14 | 8c94add99 |
15 | 51dac68db |
hex | 30f4d1e33 |
13141614131 has 2 divisors, whose sum is σ = 13141614132. Its totient is φ = 13141614130.
The previous prime is 13141614127. The next prime is 13141614133.
13141614131 is nontrivially palindromic in base 10.
It is a strong prime.
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 13141614131 - 22 = 13141614127 is a prime.
It is a super-2 number, since 2×131416141312 (a number of 21 digits) contains 22 as substring.
Together with 13141614133, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13141614131.
It is not a weakly prime, because it can be changed into another prime (13141614133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570807065 + 6570807066.
It is an arithmetic number, because the mean of its divisors is an integer number (6570807066).
Almost surely, 213141614131 is an apocalyptic number.
13141614131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13141614131 is an equidigital number, since it uses as much as digits as its factorization.
13141614131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 864, while the sum is 26.
The spelling of 13141614131 in words is "thirteen billion, one hundred forty-one million, six hundred fourteen thousand, one hundred thirty-one".
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