Base | Representation |
---|---|
bin | 10011000111111011111… |
… | …100001111010011100111 |
3 | 11122122011021220120010202 |
4 | 103013323330033103213 |
5 | 133012431111212311 |
6 | 2443421553141115 |
7 | 163642620550661 |
oct | 23077374172347 |
9 | 4578137816122 |
10 | 1314191897831 |
11 | 46738907a07a |
12 | 19284825a79b |
13 | 96c0a3b4817 |
14 | 47870335531 |
15 | 242b9d11e3b |
hex | 131fbf0f4e7 |
1314191897831 has 2 divisors, whose sum is σ = 1314191897832. Its totient is φ = 1314191897830.
The previous prime is 1314191897813. The next prime is 1314191897839. The reversal of 1314191897831 is 1387981914131.
Together with previous prime (1314191897813) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1314191897831 is a prime.
It is a super-2 number, since 2×13141918978312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314191897839) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657095948915 + 657095948916.
It is an arithmetic number, because the mean of its divisors is an integer number (657095948916).
Almost surely, 21314191897831 is an apocalyptic number.
1314191897831 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314191897831 is an equidigital number, since it uses as much as digits as its factorization.
1314191897831 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1306368, while the sum is 56.
The spelling of 1314191897831 in words is "one trillion, three hundred fourteen billion, one hundred ninety-one million, eight hundred ninety-seven thousand, eight hundred thirty-one".
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