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13142012011003 = 17773059530059
BaseRepresentation
bin1011111100111101110011…
…1101010010000111111011
31201112100211102011011020201
42333033130331102013323
53210304320033323003
643541205034503031
72524323210646111
oct277173475220773
951470742134221
1013142012011003
114207550194547
121583015294a77
1374439533b765
14336110957ab1
1517bcc1d3eb1d
hexbf3dcf521fb

13142012011003 has 4 divisors (see below), whose sum is σ = 13915071541080. Its totient is φ = 12368952480928.

The previous prime is 13142012010983. The next prime is 13142012011021. The reversal of 13142012011003 is 30011021024131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13142012011003 - 229 = 13141475140091 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13142012011703) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 386529765013 + ... + 386529765046.

It is an arithmetic number, because the mean of its divisors is an integer number (3478767885270).

Almost surely, 213142012011003 is an apocalyptic number.

13142012011003 is a deficient number, since it is larger than the sum of its proper divisors (773059530077).

13142012011003 is an equidigital number, since it uses as much as digits as its factorization.

13142012011003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 773059530076.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13142012011003 its reverse (30011021024131), we get a palindrome (43153033035134).

The spelling of 13142012011003 in words is "thirteen trillion, one hundred forty-two billion, twelve million, eleven thousand, three".

Divisors: 1 17 773059530059 13142012011003