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131420131100057 is a prime number
BaseRepresentation
bin11101111000011010100010…
…001110110000010110011001
3122020022122022220012220222002
4131320122202032300112121
5114211141412030200212
61143301324052010345
736452535234660362
oct3570324216602631
9566278286186862
10131420131100057
1138968a67987998
12128a61280009b5
135843b32a79087
142464aa8258b69
15102d814c1dac2
hex7786a23b0599

131420131100057 has 2 divisors, whose sum is σ = 131420131100058. Its totient is φ = 131420131100056.

The previous prime is 131420131100051. The next prime is 131420131100171. The reversal of 131420131100057 is 750001131024131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121000528000576 + 10419603099481 = 11000024^2 + 3227941^2 .

It is a cyclic number.

It is not a de Polignac number, because 131420131100057 - 224 = 131420114322841 is a prime.

It is not a weakly prime, because it can be changed into another prime (131420131100051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65710065550028 + 65710065550029.

It is an arithmetic number, because the mean of its divisors is an integer number (65710065550029).

Almost surely, 2131420131100057 is an apocalyptic number.

It is an amenable number.

131420131100057 is a deficient number, since it is larger than the sum of its proper divisors (1).

131420131100057 is an equidigital number, since it uses as much as digits as its factorization.

131420131100057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2520, while the sum is 29.

Adding to 131420131100057 its reverse (750001131024131), we get a palindrome (881421262124188).

The spelling of 131420131100057 in words is "one hundred thirty-one trillion, four hundred twenty billion, one hundred thirty-one million, one hundred thousand, fifty-seven".