Base | Representation |
---|---|
bin | 10011000111111100100… |
… | …011001101000000000010 |
3 | 11122122012000010111100101 |
4 | 103013330203031000002 |
5 | 133012441220041002 |
6 | 2443423000113014 |
7 | 163643103431623 |
oct | 23077443150002 |
9 | 4578160114311 |
10 | 1314202112002 |
11 | 46739391613a |
12 | 19284b76576a |
13 | 96c0c54ca00 |
14 | 47871833a4a |
15 | 242bab7d587 |
hex | 131fc8cd002 |
1314202112002 has 96 divisors (see below), whose sum is σ = 2217942853632. Its totient is φ = 583381274112.
The previous prime is 1314202111997. The next prime is 1314202112029. The reversal of 1314202112002 is 2002112024131.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 252874468 + ... + 252879664.
It is an arithmetic number, because the mean of its divisors is an integer number (23103571392).
Almost surely, 21314202112002 is an apocalyptic number.
1314202112002 is a deficient number, since it is larger than the sum of its proper divisors (903740741630).
1314202112002 is a wasteful number, since it uses less digits than its factorization.
1314202112002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5532 (or 5519 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 1314202112002 its reverse (2002112024131), we get a palindrome (3316314136133).
It can be divided in two parts, 131420 and 2112002, that added together give a palindrome (2243422).
The spelling of 1314202112002 in words is "one trillion, three hundred fourteen billion, two hundred two million, one hundred twelve thousand, two".
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