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13142036754317 is a prime number
BaseRepresentation
bin1011111100111101111001…
…1011101010111110001101
31201112100220010201020200202
42333033132123222332031
53210304342402114232
643541211321103245
72524323631162052
oct277173633527615
951470803636622
1013142036754317
114207563154569
121583021627b25
1374439a4c2b83
14336113d59029
1517bcc40cb162
hexbf3de6eaf8d

13142036754317 has 2 divisors, whose sum is σ = 13142036754318. Its totient is φ = 13142036754316.

The previous prime is 13142036754293. The next prime is 13142036754361. The reversal of 13142036754317 is 71345763024131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13012028913961 + 130007840356 = 3607219^2 + 360566^2 .

It is a cyclic number.

It is not a de Polignac number, because 13142036754317 - 242 = 8743990243213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13142036754377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571018377158 + 6571018377159.

It is an arithmetic number, because the mean of its divisors is an integer number (6571018377159).

Almost surely, 213142036754317 is an apocalyptic number.

It is an amenable number.

13142036754317 is a deficient number, since it is larger than the sum of its proper divisors (1).

13142036754317 is an equidigital number, since it uses as much as digits as its factorization.

13142036754317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1270080, while the sum is 47.

Adding to 13142036754317 its reverse (71345763024131), we get a palindrome (84487799778448).

The spelling of 13142036754317 in words is "thirteen trillion, one hundred forty-two billion, thirty-six million, seven hundred fifty-four thousand, three hundred seventeen".