131420402512003 has 4 divisors (see below), whose sum is σ = 143367711831288. Its totient is φ = 119473093192720.

The previous prime is 131420402511967. The next prime is 131420402512019. The reversal of 131420402512003 is 300215204024131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131420402512003 - 2³⁷ = 131282963558531 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131420402512703) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5973654659626 + ... + 5973654659647.

It is an arithmetic number, because the mean of its divisors is an integer number (35841927957822).

Almost surely, 2^{131420402512003} is an apocalyptic number.

131420402512003 is a deficient number, since it is larger than the sum of its proper divisors (11947309319285).

131420402512003 is a wasteful number, since it uses less digits than its factorization.

131420402512003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11947309319284.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 131420402512003 its reverse (300215204024131), we get a palindrome (431635606536134).

The spelling of 131420402512003 in words is "one hundred thirty-one trillion, four hundred twenty billion, four hundred two million, five hundred twelve thousand, three".