Base | Representation |
---|---|
bin | 1011111100111101111011… |
… | …0111011001110101000010 |
3 | 1201112100220122101121000002 |
4 | 2333033132313121311002 |
5 | 3210304401232233010 |
6 | 43541212141000002 |
7 | 2524324050030620 |
oct | 277173667316502 |
9 | 51470818347002 |
10 | 13142044024130 |
11 | 420756726a47a |
12 | 1583023b53002 |
13 | 74439bb69b38 |
14 | 336114ccc510 |
15 | 17bcc4a651a5 |
hex | bf3dedd9d42 |
13142044024130 has 16 divisors (see below), whose sum is σ = 27035061992640. Its totient is φ = 4505843665392.
The previous prime is 13142044024121. The next prime is 13142044024177. The reversal of 13142044024130 is 3142044024131.
It is a super-2 number, since 2×131420440241302 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13142044024093 and 13142044024102.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 93871742960 + ... + 93871743099.
It is an arithmetic number, because the mean of its divisors is an integer number (1689691374540).
Almost surely, 213142044024130 is an apocalyptic number.
13142044024130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13142044024130 is an abundant number, since it is smaller than the sum of its proper divisors (13893017968510).
13142044024130 is a wasteful number, since it uses less digits than its factorization.
13142044024130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 187743486073.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 13142044024130 its reverse (3142044024131), we get a palindrome (16284088048261).
Subtracting from 13142044024130 its reverse (3142044024131), we obtain a palindrome (9999999999999).
The spelling of 13142044024130 in words is "thirteen trillion, one hundred forty-two billion, forty-four million, twenty-four thousand, one hundred thirty".
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