1314210441 has 4 divisors (see below), whose sum is σ = 1752280592. Its totient is φ = 876140292.

The previous prime is 1314210383. The next prime is 1314210451. The reversal of 1314210441 is 1440124131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1440124131 = 3 ⋅480041377.

It is not a de Polignac number, because 1314210441 - 2⁶ = 1314210377 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1314210451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219035071 + ... + 219035076.

It is an arithmetic number, because the mean of its divisors is an integer number (438070148).

Almost surely, 2^1314210441 is an apocalyptic number.

It is an amenable number.

1314210441 is a deficient number, since it is larger than the sum of its proper divisors (438070151).

1314210441 is an equidigital number, since it uses as much as digits as its factorization.

1314210441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 438070150.

The product of its (nonzero) digits is 384, while the sum is 21.

The square root of 1314210441 is about 36252.0405080873. The cubic root of 1314210441 is about 1095.3551917921.

Adding to 1314210441 its reverse (1440124131), we get a palindrome (2754334572).

The spelling of 1314210441 in words is "one billion, three hundred fourteen million, two hundred ten thousand, four hundred forty-one".