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13142124013201 is a prime number
BaseRepresentation
bin1011111100111110001110…
…1000100010011010010001
31201112101010012220110101021
42333033203220202122101
53210310032221410301
643541224115235441
72524326040650121
oct277174350423221
951471105813337
1013142124013201
1142075a8433447
1215830468a8b81
137443b25c5251
14336121790c81
1517bccbab58a1
hexbf3e3a22691

13142124013201 has 2 divisors, whose sum is σ = 13142124013202. Its totient is φ = 13142124013200.

The previous prime is 13142124013147. The next prime is 13142124013237. The reversal of 13142124013201 is 10231042124131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9929910182976 + 3212213830225 = 3151176^2 + 1792265^2 .

It is a cyclic number.

It is not a de Polignac number, because 13142124013201 - 243 = 4346030990993 is a prime.

It is not a weakly prime, because it can be changed into another prime (13142124013001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571062006600 + 6571062006601.

It is an arithmetic number, because the mean of its divisors is an integer number (6571062006601).

Almost surely, 213142124013201 is an apocalyptic number.

It is an amenable number.

13142124013201 is a deficient number, since it is larger than the sum of its proper divisors (1).

13142124013201 is an equidigital number, since it uses as much as digits as its factorization.

13142124013201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13142124013201 its reverse (10231042124131), we get a palindrome (23373166137332).

The spelling of 13142124013201 in words is "thirteen trillion, one hundred forty-two billion, one hundred twenty-four million, thirteen thousand, two hundred one".