Base | Representation |
---|---|
bin | 11101111000011011101101… |
… | …111100010100010101001000 |
3 | 122020022202121102101112212212 |
4 | 131320123231330110111020 |
5 | 114211202012220210422 |
6 | 1143302054105324252 |
7 | 36452611560541520 |
oct | 3570335574242510 |
9 | 566282542345785 |
10 | 131421401335112 |
11 | 389695599a5329 |
12 | 128a6421496688 |
13 | 5843ca5c92055 |
14 | 2464b88c2c680 |
15 | 102d88b4ce9e2 |
hex | 7786edf14548 |
131421401335112 has 64 divisors (see below), whose sum is σ = 282217855104000. Its totient is φ = 56203354964736.
The previous prime is 131421401335087. The next prime is 131421401335181. The reversal of 131421401335112 is 211533104124131.
It is a super-2 number, since 2×1314214013351122 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 676645598 + ... + 676839794.
It is an arithmetic number, because the mean of its divisors is an integer number (4409653986000).
Almost surely, 2131421401335112 is an apocalyptic number.
It is an amenable number.
131421401335112 is an abundant number, since it is smaller than the sum of its proper divisors (150796453768888).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131421401335112 is a wasteful number, since it uses less digits than its factorization.
131421401335112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 219918 (or 219914 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 32.
Adding to 131421401335112 its reverse (211533104124131), we get a palindrome (342954505459243).
The spelling of 131421401335112 in words is "one hundred thirty-one trillion, four hundred twenty-one billion, four hundred one million, three hundred thirty-five thousand, one hundred twelve".
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