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1314214224423 = 3438071408141
BaseRepresentation
bin10011000111111101010…
…001011010001000100111
311122122012211220212110120
4103013331101122020213
5133013002320140143
62443424111453023
7163643311410042
oct23077521321047
94578184825416
101314214224423
1146739a739401
12192853827173
1396c11c00c19
14478732a7c59
15242bbc72383
hex131fd45a227

1314214224423 has 4 divisors (see below), whose sum is σ = 1752285632568. Its totient is φ = 876142816280.

The previous prime is 1314214224361. The next prime is 1314214224461. The reversal of 1314214224423 is 3244224124131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1314214224423 - 218 = 1314213962279 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1314214224823) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219035704068 + ... + 219035704073.

It is an arithmetic number, because the mean of its divisors is an integer number (438071408142).

Almost surely, 21314214224423 is an apocalyptic number.

1314214224423 is a deficient number, since it is larger than the sum of its proper divisors (438071408145).

1314214224423 is an equidigital number, since it uses as much as digits as its factorization.

1314214224423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 438071408144.

The product of its digits is 36864, while the sum is 33.

Adding to 1314214224423 its reverse (3244224124131), we get a palindrome (4558438348554).

The spelling of 1314214224423 in words is "one trillion, three hundred fourteen billion, two hundred fourteen million, two hundred twenty-four thousand, four hundred twenty-three".

Divisors: 1 3 438071408141 1314214224423