Base | Representation |
---|---|
bin | 1011111100111110011100… |
… | …0110110100001101010011 |
3 | 1201112101021021112211020102 |
4 | 2333033213012310031103 |
5 | 3210310142131011232 |
6 | 43541234000203015 |
7 | 2524330346144156 |
oct | 277174706641523 |
9 | 51471237484212 |
10 | 13142182282067 |
11 | 4207628311733 |
12 | 158306230946b |
13 | 7443c16b7277 |
14 | 3361293dbc9d |
15 | 17bcd1c75662 |
hex | bf3e71b4353 |
13142182282067 has 2 divisors, whose sum is σ = 13142182282068. Its totient is φ = 13142182282066.
The previous prime is 13142182282057. The next prime is 13142182282069. The reversal of 13142182282067 is 76028228124131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13142182282067 - 210 = 13142182281043 is a prime.
Together with 13142182282069, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13142182282069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571091141033 + 6571091141034.
It is an arithmetic number, because the mean of its divisors is an integer number (6571091141034).
Almost surely, 213142182282067 is an apocalyptic number.
13142182282067 is a deficient number, since it is larger than the sum of its proper divisors (1).
13142182282067 is an equidigital number, since it uses as much as digits as its factorization.
13142182282067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 516096, while the sum is 47.
The spelling of 13142182282067 in words is "thirteen trillion, one hundred forty-two billion, one hundred eighty-two million, two hundred eighty-two thousand, sixty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.634 sec. • engine limits •