Base | Representation |
---|---|
bin | 1011111100111110100110… |
… | …1010001100110100110011 |
3 | 1201112101101021010211100222 |
4 | 2333033221222030310303 |
5 | 3210310234112043441 |
6 | 43541242130203255 |
7 | 2524331406200645 |
oct | 277175152146463 |
9 | 51471337124328 |
10 | 13142225112371 |
11 | 420764a505783 |
12 | 158307472352b |
13 | 7443ca532144 |
14 | 336130d8a895 |
15 | 17bcd58d5d4b |
hex | bf3e9a8cd33 |
13142225112371 has 2 divisors, whose sum is σ = 13142225112372. Its totient is φ = 13142225112370.
The previous prime is 13142225112287. The next prime is 13142225112409. The reversal of 13142225112371 is 17321152224131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13142225112371 - 210 = 13142225111347 is a prime.
It is not a weakly prime, because it can be changed into another prime (13142225112971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571112556185 + 6571112556186.
It is an arithmetic number, because the mean of its divisors is an integer number (6571112556186).
Almost surely, 213142225112371 is an apocalyptic number.
13142225112371 is a deficient number, since it is larger than the sum of its proper divisors (1).
13142225112371 is an equidigital number, since it uses as much as digits as its factorization.
13142225112371 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20160, while the sum is 35.
The spelling of 13142225112371 in words is "thirteen trillion, one hundred forty-two billion, two hundred twenty-five million, one hundred twelve thousand, three hundred seventy-one".
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