13142234000101 has 2 divisors, whose sum is σ = 13142234000102. Its totient is φ = 13142234000100.

The previous prime is 13142234000081. The next prime is 13142234000113. The reversal of 13142234000101 is 10100043224131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9792199304001 + 3350034696100 = 3129249^2 + 1830310^2 .

It is a cyclic number.

It is not a de Polignac number, because 13142234000101 - 2¹⁵ = 13142233967333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13142234000171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571117000050 + 6571117000051.

It is an arithmetic number, because the mean of its divisors is an integer number (6571117000051).

Almost surely, 2^{13142234000101} is an apocalyptic number.

It is an amenable number.

13142234000101 is a deficient number, since it is larger than the sum of its proper divisors (1).

13142234000101 is an equidigital number, since it uses as much as digits as its factorization.

13142234000101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 13142234000101 its reverse (10100043224131), we get a palindrome (23242277224232).

The spelling of 13142234000101 in words is "thirteen trillion, one hundred forty-two billion, two hundred thirty-four million, one hundred one", and thus it is an aban number.