Base | Representation |
---|---|
bin | 1011111100111110111001… |
… | …1000110011111110001010 |
3 | 1201112101120210102002200210 |
4 | 2333033232120303332022 |
5 | 3210310414414041302 |
6 | 43541254042341550 |
7 | 2524333361364300 |
oct | 277175630637612 |
9 | 51471523362623 |
10 | 13142304440202 |
11 | 4207690267973 |
12 | 15830971ba8b6 |
13 | 744410ab85a2 |
14 | 33613b71a270 |
15 | 17bcdc85566c |
hex | bf3ee633f8a |
13142304440202 has 48 divisors (see below), whose sum is σ = 30994822599552. Its totient is φ = 3703506528960.
The previous prime is 13142304440201. The next prime is 13142304440207. The reversal of 13142304440202 is 20204440324131.
It is a self number, because there is not a number n which added to its sum of digits gives 13142304440202.
It is not an unprimeable number, because it can be changed into a prime (13142304440201) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 306154674 + ... + 306197597.
It is an arithmetic number, because the mean of its divisors is an integer number (645725470824).
Almost surely, 213142304440202 is an apocalyptic number.
13142304440202 is an abundant number, since it is smaller than the sum of its proper divisors (17852518159350).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13142304440202 is a wasteful number, since it uses less digits than its factorization.
13142304440202 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 612352363 (or 612352356 counting only the distinct ones).
The product of its (nonzero) digits is 18432, while the sum is 30.
Adding to 13142304440202 its reverse (20204440324131), we get a palindrome (33346744764333).
The spelling of 13142304440202 in words is "thirteen trillion, one hundred forty-two billion, three hundred four million, four hundred forty thousand, two hundred two".
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