13142304445541 has 4 divisors (see below), whose sum is σ = 13226013391212. Its totient is φ = 13058595499872.

The previous prime is 13142304445427. The next prime is 13142304445549. The reversal of 13142304445541 is 14554440324131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2959504343041 + 10182800102500 = 1720321^2 + 3191050^2 .

It is a cyclic number.

It is not a de Polignac number, because 13142304445541 - 2³⁸ = 12867426538597 is a prime.

It is a super-3 number, since 3×13142304445541³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13142304445549) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41854472600 + ... + 41854472913.

It is an arithmetic number, because the mean of its divisors is an integer number (3306503347803).

Almost surely, 2^{13142304445541} is an apocalyptic number.

It is an amenable number.

13142304445541 is a deficient number, since it is larger than the sum of its proper divisors (83708945671).

13142304445541 is an equidigital number, since it uses as much as digits as its factorization.

13142304445541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83708945670.

The product of its (nonzero) digits is 460800, while the sum is 41.

Adding to 13142304445541 its reverse (14554440324131), we get a palindrome (27696744769672).

The spelling of 13142304445541 in words is "thirteen trillion, one hundred forty-two billion, three hundred four million, four hundred forty-five thousand, five hundred forty-one".