Base | Representation |
---|---|
bin | 11101111000011101010101… |
… | …000100000100100110110111 |
3 | 122020022221001222212000201002 |
4 | 131320131111010010212313 |
5 | 114211214033120433421 |
6 | 1143302541511153515 |
7 | 36453002466201155 |
oct | 3570352504044667 |
9 | 566287058760632 |
10 | 131423131421111 |
11 | 3896a267547572 |
12 | 128a682497589b |
13 | 58441c054378a |
14 | 2464cb09063d5 |
15 | 102d93d327b0b |
hex | 7787551049b7 |
131423131421111 has 2 divisors, whose sum is σ = 131423131421112. Its totient is φ = 131423131421110.
The previous prime is 131423131421077. The next prime is 131423131421117. The reversal of 131423131421111 is 111124131324131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131423131421111 - 214 = 131423131404727 is a prime.
It is a super-2 number, since 2×1314231314211112 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131423131421117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65711565710555 + 65711565710556.
It is an arithmetic number, because the mean of its divisors is an integer number (65711565710556).
Almost surely, 2131423131421111 is an apocalyptic number.
131423131421111 is a deficient number, since it is larger than the sum of its proper divisors (1).
131423131421111 is an equidigital number, since it uses as much as digits as its factorization.
131423131421111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1728, while the sum is 29.
Adding to 131423131421111 its reverse (111124131324131), we get a palindrome (242547262745242).
The spelling of 131423131421111 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, one hundred thirty-one million, four hundred twenty-one thousand, one hundred eleven".
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