Base | Representation |
---|---|
bin | 111101001100101101… |
… | …1100000000010100011 |
3 | 110120020002211100111200 |
4 | 1322121123200002203 |
5 | 4123123311021201 |
6 | 140212554012243 |
7 | 12331534163355 |
oct | 1723133400243 |
9 | 416202740450 |
10 | 131423142051 |
11 | 50810a34893 |
12 | 21579417083 |
13 | c515996916 |
14 | 650a4c30d5 |
15 | 3642c7a386 |
hex | 1e996e00a3 |
131423142051 has 6 divisors (see below), whose sum is σ = 189833427420. Its totient is φ = 87615428028.
The previous prime is 131423142043. The next prime is 131423142061. The reversal of 131423142051 is 150241324131.
131423142051 is a `hidden beast` number, since 1 + 3 + 1 + 4 + 231 + 420 + 5 + 1 = 666.
It is not a de Polignac number, because 131423142051 - 23 = 131423142043 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131423142031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 7301285661 + ... + 7301285678.
It is an arithmetic number, because the mean of its divisors is an integer number (31638904570).
Almost surely, 2131423142051 is an apocalyptic number.
131423142051 is a deficient number, since it is larger than the sum of its proper divisors (58410285369).
131423142051 is a wasteful number, since it uses less digits than its factorization.
131423142051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14602571345 (or 14602571342 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 131423142051 its reverse (150241324131), we get a palindrome (281664466182).
The spelling of 131423142051 in words is "one hundred thirty-one billion, four hundred twenty-three million, one hundred forty-two thousand, fifty-one".
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