Base | Representation |
---|---|
bin | 11101111000011101010101… |
… | …101101001111000110100011 |
3 | 122020022221002202011021000202 |
4 | 131320131111231033012203 |
5 | 114211214043401241003 |
6 | 1143302542534335415 |
7 | 36453002660003405 |
oct | 3570352555170643 |
9 | 566287082137022 |
10 | 131423142212003 |
11 | 3896a272647964 |
12 | 128a68284ba56b |
13 | 58441c2851315 |
14 | 2464cb2114b75 |
15 | 102d93e25a088 |
hex | 778755b4f1a3 |
131423142212003 has 2 divisors, whose sum is σ = 131423142212004. Its totient is φ = 131423142212002.
The previous prime is 131423142211987. The next prime is 131423142212051. The reversal of 131423142212003 is 300212241324131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131423142212003 - 24 = 131423142211987 is a prime.
It is not a weakly prime, because it can be changed into another prime (131423142212503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65711571106001 + 65711571106002.
It is an arithmetic number, because the mean of its divisors is an integer number (65711571106002).
Almost surely, 2131423142212003 is an apocalyptic number.
131423142212003 is a deficient number, since it is larger than the sum of its proper divisors (1).
131423142212003 is an equidigital number, since it uses as much as digits as its factorization.
131423142212003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 131423142212003 its reverse (300212241324131), we get a palindrome (431635383536134).
The spelling of 131423142212003 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, one hundred forty-two million, two hundred twelve thousand, three".
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