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131423143343113 is a prime number
BaseRepresentation
bin11101111000011101010101…
…110001100011010000001001
3122020022221002211021201121201
4131320131111301203100021
5114211214044143434423
61143302543014504201
736453003002424166
oct3570352561432011
9566287084251551
10131423143343113
113896a27324a766
12128a6828965061
1358441c2b5910b
142464cb232b06d
15102d93e3d02ad
hex778755c63409

131423143343113 has 2 divisors, whose sum is σ = 131423143343114. Its totient is φ = 131423143343112.

The previous prime is 131423143343039. The next prime is 131423143343159. The reversal of 131423143343113 is 311343341324131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 74049002359929 + 57374140983184 = 8605173^2 + 7574572^2 .

It is a cyclic number.

It is not a de Polignac number, because 131423143343113 - 213 = 131423143334921 is a prime.

It is not a weakly prime, because it can be changed into another prime (131423143343213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65711571671556 + 65711571671557.

It is an arithmetic number, because the mean of its divisors is an integer number (65711571671557).

Almost surely, 2131423143343113 is an apocalyptic number.

It is an amenable number.

131423143343113 is a deficient number, since it is larger than the sum of its proper divisors (1).

131423143343113 is an equidigital number, since it uses as much as digits as its factorization.

131423143343113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 93312, while the sum is 37.

Adding to 131423143343113 its reverse (311343341324131), we get a palindrome (442766484667244).

The spelling of 131423143343113 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, one hundred forty-three million, three hundred forty-three thousand, one hundred thirteen".