Base | Representation |
---|---|
bin | 10011000111111110010… |
… | …011011110110010100101 |
3 | 11122122021001111211211022 |
4 | 103013332103132302211 |
5 | 133013021233414442 |
6 | 2443425531020525 |
7 | 163643611546250 |
oct | 23077623366245 |
9 | 4578231454738 |
10 | 1314231544997 |
11 | 4673a9499628 |
12 | 19285959a745 |
13 | 96c15686897 |
14 | 478756d6097 |
15 | 242bd5443d2 |
hex | 131fe4deca5 |
1314231544997 has 16 divisors (see below), whose sum is σ = 1608199505280. Its totient is φ = 1048307808768.
The previous prime is 1314231544987. The next prime is 1314231545027. The reversal of 1314231544997 is 7994451324131.
It is a cyclic number.
It is not a de Polignac number, because 1314231544997 - 24 = 1314231544981 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1314231544907) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 62034143 + ... + 62055324.
It is an arithmetic number, because the mean of its divisors is an integer number (100512469080).
Almost surely, 21314231544997 is an apocalyptic number.
1314231544997 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
It is an amenable number.
1314231544997 is a deficient number, since it is larger than the sum of its proper divisors (293967960283).
1314231544997 is a wasteful number, since it uses less digits than its factorization.
1314231544997 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 124089580.
The product of its digits is 3265920, while the sum is 53.
The spelling of 1314231544997 in words is "one trillion, three hundred fourteen billion, two hundred thirty-one million, five hundred forty-four thousand, nine hundred ninety-seven".
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