Base | Representation |
---|---|
bin | 111101001100101101… |
… | …1100101101010111111 |
3 | 110120020002212112011001 |
4 | 1322121123211222333 |
5 | 4123123312240434 |
6 | 140212554311131 |
7 | 12331534320541 |
oct | 1723133455277 |
9 | 416202775131 |
10 | 131423165119 |
11 | 50810a50154 |
12 | 215794284a7 |
13 | c5159a427c |
14 | 650a4cb691 |
15 | 3642c82114 |
hex | 1e996e5abf |
131423165119 has 2 divisors, whose sum is σ = 131423165120. Its totient is φ = 131423165118.
The previous prime is 131423165087. The next prime is 131423165131. The reversal of 131423165119 is 911561324131.
It is a strong prime.
It is an emirp because it is prime and its reverse (911561324131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131423165119 - 25 = 131423165087 is a prime.
It is a super-2 number, since 2×1314231651192 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131423165719) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65711582559 + 65711582560.
It is an arithmetic number, because the mean of its divisors is an integer number (65711582560).
Almost surely, 2131423165119 is an apocalyptic number.
131423165119 is a deficient number, since it is larger than the sum of its proper divisors (1).
131423165119 is an equidigital number, since it uses as much as digits as its factorization.
131423165119 is an evil number, because the sum of its binary digits is even.
The product of its digits is 19440, while the sum is 37.
The spelling of 131423165119 in words is "one hundred thirty-one billion, four hundred twenty-three million, one hundred sixty-five thousand, one hundred nineteen".
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