Base | Representation |
---|---|
bin | 11101111000011101100000… |
… | …111101100000000100011111 |
3 | 122020022221120220102222000111 |
4 | 131320131200331200010133 |
5 | 114211214440220301213 |
6 | 1143303013401310451 |
7 | 36453010441616221 |
oct | 3570354075400437 |
9 | 566287526388014 |
10 | 131423331025183 |
11 | 3896a35a18a00a |
12 | 128a687b795427 |
13 | 58442229bc7b2 |
14 | 2464ccd224411 |
15 | 102d950b04a3d |
hex | 778760f6011f |
131423331025183 has 2 divisors, whose sum is σ = 131423331025184. Its totient is φ = 131423331025182.
The previous prime is 131423331025139. The next prime is 131423331025289. The reversal of 131423331025183 is 381520133324131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131423331025183 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131423331023183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65711665512591 + 65711665512592.
It is an arithmetic number, because the mean of its divisors is an integer number (65711665512592).
Almost surely, 2131423331025183 is an apocalyptic number.
131423331025183 is a deficient number, since it is larger than the sum of its proper divisors (1).
131423331025183 is an equidigital number, since it uses as much as digits as its factorization.
131423331025183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 40.
The spelling of 131423331025183 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, three hundred thirty-one million, twenty-five thousand, one hundred eighty-three".
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