13142340024531 has 4 divisors (see below), whose sum is σ = 17523120032712. Its totient is φ = 8761560016352.

The previous prime is 13142340024481. The next prime is 13142340024571. The reversal of 13142340024531 is 13542004324131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13142340024531 - 2¹³ = 13142340016339 is a prime.

It is a super-2 number, since 2×13142340024531² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13142340024492 and 13142340024501.

It is not an unprimeable number, because it can be changed into a prime (13142340024571) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2190390004086 + ... + 2190390004091.

It is an arithmetic number, because the mean of its divisors is an integer number (4380780008178).

Almost surely, 2^{13142340024531} is an apocalyptic number.

13142340024531 is a deficient number, since it is larger than the sum of its proper divisors (4380780008181).

13142340024531 is an equidigital number, since it uses as much as digits as its factorization.

13142340024531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4380780008180.

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 13142340024531 its reverse (13542004324131), we get a palindrome (26684344348662).

The spelling of 13142340024531 in words is "thirteen trillion, one hundred forty-two billion, three hundred forty million, twenty-four thousand, five hundred thirty-one".