Base | Representation |
---|---|
bin | 10011000111111110011… |
… | …100111000101110011101 |
3 | 11122122021020011002220011 |
4 | 103013332130320232131 |
5 | 133013022401314100 |
6 | 2443430055523221 |
7 | 163643641525342 |
oct | 23077634705635 |
9 | 4578236132804 |
10 | 1314234010525 |
11 | 4673aa922a57 |
12 | 19285a389511 |
13 | 96c1603ab87 |
14 | 47875b787c9 |
15 | 242bd87ebba |
hex | 131fe738b9d |
1314234010525 has 6 divisors (see below), whose sum is σ = 1629650173082. Its totient is φ = 1051387208400.
The previous prime is 1314234010493. The next prime is 1314234010547. The reversal of 1314234010525 is 5250104324131.
It can be written as a sum of positive squares in 3 ways, for example, as 249794042436 + 1064439968089 = 499794^2 + 1031717^2 .
It is not a de Polignac number, because 1314234010525 - 25 = 1314234010493 is a prime.
It is a super-2 number, since 2×13142340105252 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 26284680186 + ... + 26284680235.
Almost surely, 21314234010525 is an apocalyptic number.
It is an amenable number.
1314234010525 is a deficient number, since it is larger than the sum of its proper divisors (315416162557).
1314234010525 is an equidigital number, since it uses as much as digits as its factorization.
1314234010525 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52569360431 (or 52569360426 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 1314234010525 its reverse (5250104324131), we get a palindrome (6564338334656).
The spelling of 1314234010525 in words is "one trillion, three hundred fourteen billion, two hundred thirty-four million, ten thousand, five hundred twenty-five".
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