Base | Representation |
---|---|
bin | 1011111100111111000101… |
… | …1000110010101010100100 |
3 | 1201112101201022002221101202 |
4 | 2333033301120302222210 |
5 | 3210311020310012000 |
6 | 43541303041142032 |
7 | 2524334542221221 |
oct | 277176130625244 |
9 | 51471638087352 |
10 | 13142354766500 |
11 | 4207706710853 |
12 | 15830b002a918 |
13 | 74441b35936b |
14 | 33614429a948 |
15 | 17bce1e96dd5 |
hex | bf3f1632aa4 |
13142354766500 has 48 divisors (see below), whose sum is σ = 29313602922240. Its totient is φ = 5145092069600.
The previous prime is 13142354766413. The next prime is 13142354766503. The reversal of 13142354766500 is 566745324131.
It is a Harshad number since it is a multiple of its sum of digits (47).
It is not an unprimeable number, because it can be changed into a prime (13142354766503) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 279601070 + ... + 279648069.
It is an arithmetic number, because the mean of its divisors is an integer number (610700060880).
Almost surely, 213142354766500 is an apocalyptic number.
13142354766500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13142354766500 is an abundant number, since it is smaller than the sum of its proper divisors (16171248155740).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13142354766500 is a wasteful number, since it uses less digits than its factorization.
13142354766500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 559249205 (or 559249193 counting only the distinct ones).
The product of its (nonzero) digits is 1814400, while the sum is 47.
The spelling of 13142354766500 in words is "thirteen trillion, one hundred forty-two billion, three hundred fifty-four million, seven hundred sixty-six thousand, five hundred".
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