Base | Representation |
---|---|
bin | 11101111000011110001001… |
… | …101111111011000001101001 |
3 | 122020100000100121002022201102 |
4 | 131320132021233323001221 |
5 | 114211222340411101213 |
6 | 1143303205324331145 |
7 | 36453033421255166 |
oct | 3570361157730151 |
9 | 566300317068642 |
10 | 131424015331433 |
11 | 3896a68048a470 |
12 | 128a6a309a3ab5 |
13 | 58443016c5836 |
14 | 2464d5607506d |
15 | 102d990c27158 |
hex | 778789bfb069 |
131424015331433 has 8 divisors (see below), whose sum is σ = 143383558211616. Its totient is φ = 119466456638400.
The previous prime is 131424015331421. The next prime is 131424015331487. The reversal of 131424015331433 is 334133510424131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131424015331433 - 210 = 131424015330409 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131424015331033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 495908288 + ... + 496173233.
It is an arithmetic number, because the mean of its divisors is an integer number (17922944776452).
Almost surely, 2131424015331433 is an apocalyptic number.
It is an amenable number.
131424015331433 is a deficient number, since it is larger than the sum of its proper divisors (11959542880183).
131424015331433 is a wasteful number, since it uses less digits than its factorization.
131424015331433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 992093575.
The product of its (nonzero) digits is 155520, while the sum is 38.
Adding to 131424015331433 its reverse (334133510424131), we get a palindrome (465557525755564).
The spelling of 131424015331433 in words is "one hundred thirty-one trillion, four hundred twenty-four billion, fifteen million, three hundred thirty-one thousand, four hundred thirty-three".
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