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131424213130351 is a prime number
BaseRepresentation
bin11101111000011110010101…
…100010011101110001101111
3122020100000212101021112211021
4131320132111202131301233
5114211223242030132401
61143303241112035011
736453041342444341
oct3570362542356157
9566300771245737
10131424213130351
113896a7720a9749
12128a6a87092a67
13584433368c00b
142464d74443291
15102d9a32992a1
hex77879589dc6f

131424213130351 has 2 divisors, whose sum is σ = 131424213130352. Its totient is φ = 131424213130350.

The previous prime is 131424213130333. The next prime is 131424213130493. The reversal of 131424213130351 is 153031312424131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131424213130351 - 211 = 131424213128303 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131424213133351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65712106565175 + 65712106565176.

It is an arithmetic number, because the mean of its divisors is an integer number (65712106565176).

Almost surely, 2131424213130351 is an apocalyptic number.

131424213130351 is a deficient number, since it is larger than the sum of its proper divisors (1).

131424213130351 is an equidigital number, since it uses as much as digits as its factorization.

131424213130351 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 34.

Adding to 131424213130351 its reverse (153031312424131), we get a palindrome (284455525554482).

The spelling of 131424213130351 in words is "one hundred thirty-one trillion, four hundred twenty-four billion, two hundred thirteen million, one hundred thirty thousand, three hundred fifty-one".