131424403333 has 8 divisors (see below), whose sum is σ = 136399142880. Its totient is φ = 126479188080.

The previous prime is 131424403303. The next prime is 131424403367. The reversal of 131424403333 is 333304424131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131424403333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131424403295 and 131424403304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131424403303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7372003 + ... + 7389808.

It is an arithmetic number, because the mean of its divisors is an integer number (17049892860).

Almost surely, 2^131424403333 is an apocalyptic number.

It is an amenable number.

131424403333 is a deficient number, since it is larger than the sum of its proper divisors (4974739547).

131424403333 is a wasteful number, since it uses less digits than its factorization.

131424403333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14762147.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 131424403333 its reverse (333304424131), we get a palindrome (464728827464).

The spelling of 131424403333 in words is "one hundred thirty-one billion, four hundred twenty-four million, four hundred three thousand, three hundred thirty-three".