Base | Representation |
---|---|
bin | 111101001100110000… |
… | …0101011100101000011 |
3 | 110120020012101100022101 |
4 | 1322121200223211003 |
5 | 4123124133000120 |
6 | 140213043051231 |
7 | 12331551550453 |
oct | 1723140534503 |
9 | 416205340271 |
10 | 131424500035 |
11 | 50811782094 |
12 | 21579970b17 |
13 | c516050a6a |
14 | 650a757d63 |
15 | 3642e4790a |
hex | 1e9982b943 |
131424500035 has 8 divisors (see below), whose sum is σ = 157717302480. Its totient is φ = 105134331744.
The previous prime is 131424500033. The next prime is 131424500047. The reversal of 131424500035 is 530005424131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131424500035 - 21 = 131424500033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131424499976 and 131424500012.
It is not an unprimeable number, because it can be changed into a prime (131424500033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 547057 + ... + 749746.
It is an arithmetic number, because the mean of its divisors is an integer number (19714662810).
Almost surely, 2131424500035 is an apocalyptic number.
131424500035 is a deficient number, since it is larger than the sum of its proper divisors (26292802445).
131424500035 is a wasteful number, since it uses less digits than its factorization.
131424500035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1317077.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 131424500035 its reverse (530005424131), we get a palindrome (661429924166).
The spelling of 131424500035 in words is "one hundred thirty-one billion, four hundred twenty-four million, five hundred thousand, thirty-five".
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